If $\overline { \overline { X } }$ = 161 $\bar { R }$

Multiple Choice

If $\overline { \overline { X } }$

= 16.1, $\bar { R }$
= ) 03,and n = 6,and if the specifications are [15.9,16.3],is the process capable?

A) Yes
B) No
$$\mathrm { NTL } = 16.1 \pm 3 \left( \frac { 0.03 } { 2.534 } \right) = 16.065 \text { to } 16.135$$