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The Balanced Equation for a Spontaneous Reaction Which Involves the Tin

Question 34

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The balanced equation for a spontaneous reaction which involves the tin and zinc redox couple using the following standard reduction potentials in acid solution is: O2+4H++4e2H2OE=+1.23 VSn4++2eSn2+E=+0.13 VZn2++2eZn( s)E=0.76 V\begin{array}{ll}\mathrm{O}_{2}+4 \mathrm{H}^{+}+4 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} & \mathrm{E}^{\circ}=+1.23 \mathrm{~V} \\\mathrm{Sn}^{4+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sn}^{2+} & \mathrm{E}^{\circ}=+0.13 \mathrm{~V} \\\mathrm{Zn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Zn}(\mathrm{~s}) & \mathrm{E}^{\circ}=-0.76 \mathrm{~V}\end{array} Zn + Sn4+ \rarr Zn2+ + Sn2+

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