For the Reaction SbCl₅(g) $\leftrightharpoons$ SbCl₃(g) + Cl₂(g) $\Delta$ G ^$\circ$ _f (SbCl₅) = -334

Multiple Choice

For the reaction SbCl₅(g) $\leftrightharpoons$ SbCl₃(g) + Cl₂(g) ,
$\Delta$ G ^$\circ$ _f (SbCl₅) = -334.34 kJ/mol
$\Delta$ G ^$\circ$ _f (SbCl₃) = -301.25 kJ/mol
$\Delta$ H ^$\circ$ _f (SbCl₅) = -394.34 kJ/mol
$\Delta$ H ^$\circ$ _f (SbCl₃) = -313.80 kJ/mol
Calculate the value of the equilibrium constant (K_p) for this reaction at 298 K.

A) 1.38 * 10^-6
B) 1.58 * 10^-6
C) 1.78 * 10^-6
D) 1.98 * 10^-6
E) None of the above