The Bond Enthalpy of the Br-Cl Bond Is Equal To \Delta

Multiple Choice

The bond enthalpy of the Br-Cl bond is equal to $\Delta$ E ^$\circ$ for the reaction BrCl(g) $\rarr$ Br(g) + Cl(g) .Use the following data to find the bond enthalpy of the Br-Cl bond. $\begin{array}{ll}\mathrm{Br}_{2}(\mathrm{l}) \rightarrow \mathrm{Br}_{2}(\mathrm{~g}) & \Delta \mathrm{H}^{\circ}=30.91 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{Br}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{Br}(\mathrm{~g}) & \Delta \mathrm{H}^{\circ}=192.9 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{Cl}(\mathrm{~g}) & \Delta \mathrm{H}^{\circ}=243.4 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{Br}_{2}(\mathrm{l}) +\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{BrCl}(\mathrm{~g}) & \Delta \mathrm{H}^{\circ}=29.2 \mathrm{~kJ} / \mathrm{mol}\end{array}$

A) 14.6 kJ/mol
B) 203.5 kJ/mol
C) 219.0 kJ/mol
D) 438.0 kJ/mol
E) 407.0 kJ/mol