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If 2Mg(s) + O2(g) \rarr 2MgO(s) Δ\Delta H \circ = -1203 \rarr MgO(s), the Enthalpy Change Is

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If 2Mg(s) + O2(g) \rarr 2MgO(s), Δ\Delta H \circ = -1203.6 kJ/mol, then for
Mg(s) + (1/2)O2(g) \rarr MgO(s), the enthalpy change is \circ H = -601.8 kJ/mol.

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