Multiple Choice
How many grams of CaCl2 are formed when 35.00 mL of 0.00237 M Ca(OH) 2 reacts with excess Cl2 gas?
2 Ca(OH) 2(aq) + 2 Cl2(g) → Ca(OCl) 2(aq) + CaCl2(s) + 2 H2O(l)
A) 0) 00460 g
B) 0) 00921 g
C) 0) 0184 g
D) 0) 0217 g
Correct Answer:

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Correct Answer:
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