Solved

The Balanced Equation for the Solubility Equilibrium of Fe(OH)2 Is

Question 24

Multiple Choice

The balanced equation for the solubility equilibrium of Fe(OH) 2 is shown below.What is the equilibrium constant expression for the Ksp of Fe(OH) 2?
Fe(OH) 2(s) ⇌ Fe2+(aq) + 2 OH-(aq)


A) Ksp = {[Fe2+][OH-]2}/{[Fe(OH) 2][H2O]}
B) Ksp = {[Fe2+][OH-]2}/[Fe(OH) 2]
C) Ksp = [Fe2+][OH-]2
D) Ksp = 1/{[Fe2+][OH-]2}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions