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Assume That You Are Testing the Difference in the Means

Question 69

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Assume that you are testing the difference in the means of two independent populations at the 0.05 level of significance.The null hypothesis is: Assume that you are testing the difference in the means of two independent populations at the 0.05 level of significance.The null hypothesis is: : - ≥ 0 and you have found the test statistic is z = -1.92.What should you conclude? A) The mean of pop.A is greater than the mean of pop.B because p < α. B) The mean of pop.A is greater than the mean of pop.B because p > α. C) There is no significant difference in the two means because p > α. D) The mean of pop.B is greater than the mean of pop.A because p < α. : Assume that you are testing the difference in the means of two independent populations at the 0.05 level of significance.The null hypothesis is: : - ≥ 0 and you have found the test statistic is z = -1.92.What should you conclude? A) The mean of pop.A is greater than the mean of pop.B because p < α. B) The mean of pop.A is greater than the mean of pop.B because p > α. C) There is no significant difference in the two means because p > α. D) The mean of pop.B is greater than the mean of pop.A because p < α. - Assume that you are testing the difference in the means of two independent populations at the 0.05 level of significance.The null hypothesis is: : - ≥ 0 and you have found the test statistic is z = -1.92.What should you conclude? A) The mean of pop.A is greater than the mean of pop.B because p < α. B) The mean of pop.A is greater than the mean of pop.B because p > α. C) There is no significant difference in the two means because p > α. D) The mean of pop.B is greater than the mean of pop.A because p < α. ≥ 0 and you have found the test statistic is z = -1.92.What should you conclude?


A) The mean of pop.A is greater than the mean of pop.B because p < α.
B) The mean of pop.A is greater than the mean of pop.B because p > α.
C) There is no significant difference in the two means because p > α.
D) The mean of pop.B is greater than the mean of pop.A because p < α.

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