Multiple Choice
How many grams of CaCl2 are formed when 15.00 mL of 0.00237 mol L-1 Ca(OH) 2(aq) reacts with excess Cl2 gas?
2 Ca(OH) 2(aq) + 2 Cl2(g) → Ca(OCl) 2(aq) + CaCl2(s) + 2 H2O(l)
A) 0.00197 g
B) 0.00394 g
C) 0.00789 g
D) 0.0507 g
Correct Answer:
Verified
Correct Answer:
Verified
Related Questions
Q20: Sodium metal and water react to form
Q21: If the percent yield is 82.0%,how many
Q22: What is the concentration of FeCl<sub>3</sub> in
Q23: What is the sum of the coefficients
Q24: In a chemical equation,Δ above the yield
Q26: 24.0 g of ethane (C<sub>2</sub>H<sub>6</sub>)are burned to
Q27: 45.8 mL of a 3.14 M sodium
Q28: There are _ mol of bromide ions
Q29: Which of the following processes could theoretically
Q30: What volume of a 0.540 mol L<sup>-1</sup>