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Lead Ions Can Be Precipitated from Aqueous Solutions by the Addition

Question 94

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Lead ions can be precipitated from aqueous solutions by the addition of aqueous iodide: Lead ions can be precipitated from aqueous solutions by the addition of aqueous iodide:   (aq) +   (aq) →   (s)  Lead iodide is virtually insoluble in water so that the reaction appears to go to completion.How many millilitres of 3.550 mol L<sup>-1</sup> HI(aq) must be added to a solution containing 0.700 mol of   To completely precipitate the lead? A) 2.54 × 10<sup>-3</sup> mL B) 394 mL C) 197 mL D) 0.197 mL E) 0.394 mL
(aq) + Lead ions can be precipitated from aqueous solutions by the addition of aqueous iodide:   (aq) +   (aq) →   (s)  Lead iodide is virtually insoluble in water so that the reaction appears to go to completion.How many millilitres of 3.550 mol L<sup>-1</sup> HI(aq) must be added to a solution containing 0.700 mol of   To completely precipitate the lead? A) 2.54 × 10<sup>-3</sup> mL B) 394 mL C) 197 mL D) 0.197 mL E) 0.394 mL
(aq) → Lead ions can be precipitated from aqueous solutions by the addition of aqueous iodide:   (aq) +   (aq) →   (s)  Lead iodide is virtually insoluble in water so that the reaction appears to go to completion.How many millilitres of 3.550 mol L<sup>-1</sup> HI(aq) must be added to a solution containing 0.700 mol of   To completely precipitate the lead? A) 2.54 × 10<sup>-3</sup> mL B) 394 mL C) 197 mL D) 0.197 mL E) 0.394 mL
(s)
Lead iodide is virtually insoluble in water so that the reaction appears to go to completion.How many millilitres of 3.550 mol L-1 HI(aq) must be added to a solution containing 0.700 mol of Lead ions can be precipitated from aqueous solutions by the addition of aqueous iodide:   (aq) +   (aq) →   (s)  Lead iodide is virtually insoluble in water so that the reaction appears to go to completion.How many millilitres of 3.550 mol L<sup>-1</sup> HI(aq) must be added to a solution containing 0.700 mol of   To completely precipitate the lead? A) 2.54 × 10<sup>-3</sup> mL B) 394 mL C) 197 mL D) 0.197 mL E) 0.394 mL
To completely precipitate the lead?


A) 2.54 × 10-3 mL
B) 394 mL
C) 197 mL
D) 0.197 mL
E) 0.394 mL

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