Multiple Choice
When [Ni(NH3) 4]2+ is treated with concentrated HCl(aq) ,two compounds having the same formula,[Ni(NH3) 4Cl2],designated I and II,are formed.Compound I can be converted to compound II by boiling it in dilute HCl(aq) .A solution of I reacts with oxalic acid,H2C2O4,to form [Ni(NH3) 4(C2O4) ].Compound II does not react with oxalic acid.Compound II is:
A) the cis isomer
B) tetrahedral in shape
C) the trans isomer
D) the same as compound I
E) octahedral in shape
Correct Answer:
Verified
Correct Answer:
Verified
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