If P(B)> 0 and Events a and B Are Independent,then $\cap$

Multiple Choice

If P(B) > 0 and events A and B are independent,then:

A) P(A) = P(B)
B) P(A | B) = P(A)
C) P(A $\cap$ B) = 0
D) P(A $\cap$ B) = P(A) $\times$ P(B $\cup$ A)
E) P(A) + P(B) = 0