Solved

The Number of Ways to Arrange X Successes Among N n/x!n / x!

Question 103

Multiple Choice

The number of ways to arrange x successes among n trials is equal to


A) n/x!n / x!
B) n!(nx) !\frac { n ! } { ( n - x ) ! }
C) n/xn / x
D) n!/x!n ! / x !
E) n!x!(nx) !\frac { n ! } { x ! ( n - x ) ! }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions