ANOVA Table Post Hoc Analysis
Tukey Simultaneous Comparison T-Values $($

Multiple Choice

ANOVA table
$\begin{array}{lrrrr}\hline\text { Source } & S S & d f & M S & F &p \text {-value }\\\hline \text { Treatment } & 6.000 & 3 & 1.9998 & 18.85&3.4E-05\\\hline\text { Error } & 1.486 & 14 & 0.1061 & \\\hline\text { Total } & 7.485 & 17 & &\end{array}$
Post hoc analysis
Tukey simultaneous comparison t-values $($ d.f. $=14)$
$\begin{array}{ccccc}&\text { Brand 3 }   \text { Brand 2 }  \text { Brand 4 }  \text { Brand 1 } \\&\quad1.40 \quad 2.28 \quad 2.58 \quad 2.95\\\begin{array}{ll}\text { Brand 3 } & 1.40 \\\text { Brand 2 } & 2.28 \\\text { Brand 4 } & 2.58 \\\text { Brand 1 } & 2.95\end{array}&\begin{array}{|l|l|l|l|}\hline & & & \\\hline 4.27 & & & \\\hline 5.38 & 1.35 & & \\\hline 7.09 & 3.07 & 1.63 &\quad\quad \\\hline\end{array}\end{array}$
The Excel/Mega-Stat output given above summarizes the results of a one-way analysis of variance in an attempt to compare the performance characteristics of four brands of vacuum cleaners. The response variable is the amount of time it takes to clean a specific size room with a specific amount of dirt.

-Use the information above and determine an individual 95% confidence interval confidence interval for $\mu _ { 1 } - \mu _ { 2 }$
) The mean and sample sizes for brand 1 and brand 2 are as follows: $\bar { x } _ { 1 }$
= 2) 95, $\bar { x } _ { 2 }$
= 2) 28,n₁ = 4 and n₂ = 5.

A) 2013 to 1.1387
B) 2852 to 1.0547
C) -.228 to 1.5680
D) 4515 to .8885
E) It cannot be determined with the information given.