Essay
If 73.5 mL of 0.200 M KI(aq)was required to precipitate all of the lead(II)ion from an aqueous solution of lead(II)nitrate, how many moles of Pb2+ were originally in the solution?
Correct Answer:
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7.35 × 10-3 ...View Answer
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Correct Answer:
Verified
7.35 × 10-3 ...
View Answer
Unlock this answer now
Get Access to more Verified Answers free of charge
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