Solved

The Heat of Neutralization of HCl by NaOH Is Δ\Delta H°rxn = -56

Question 7

Short Answer

The heat of neutralization of HCl by NaOH is Δ\Delta H°rxn = -56.2 kJ/mol.How much heat is released when 125 mL of 1.750 M HCl is mixed with 195 mL of 0.667 M NaOH?

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q2: Calculate the enthalpy of reaction for

Q3: The combustion of butane produces heat

Q4: A 0.3423 g sample of pentane, C<sub>5</sub>H<sub>12</sub>,

Q5: How much heat (kJ)is evolved when

Q8: Which of the following has a

Q9: Define specific heat.

Q10: The combustion of one mole of benzene,

Q11: Styrene, C<sub>8</sub>H<sub>8</sub>, is one of the

Q12: Ozone (O<sub>3</sub>)in the atmosphere can be

Q14: According to the first law of thermodynamics:<br>A)