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The Equilibrium Expression for the Ionization of a Weak Monoprotic

Question 178

Multiple Choice

The equilibrium expression for the ionization of a weak monoprotic acid, HA, in water is:


A) Ka = [HA]/[OH-][H3O+]
B) Ka = [OH-][H3O+]/[HA]
C) Ka = [H3O+][HA]/[A-]
D) Ka = [H3O+][A-]/[HA]
E) Ka = [HA]/[H3O+][A-]

Correct Answer:

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