Solved

The Acid-Dissociation Constants of Sulfurous Acid (H2SO3)are Kal = 1

Question 15

Multiple Choice

The acid-dissociation constants of sulfurous acid (H2SO3) are Kal = 1.7 × 10-2 and Ka2 = 6.4 × 10-8 at 25.0°C. Calculate the pH of a 0.163 M aqueous solution of sulfurous acid.


A) 4.53
B) 1.28
C) 1.86
D) 6.21
E) 1.93

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q10: K<sub>b</sub> for NH<sub>3</sub> is 1.8 × 10<sup>-5</sup>.

Q11: In which of the following aqueous solutions

Q12: The conjugate base of H<sub>2</sub>PO<sub>4</sub><sup>-</sup> is _.<br>A)PO<sub>4</sub><sup>-3</sup><br>B)H<sub>2</sub>PO<sub>4</sub><br>C)H<sub>3</sub>PO<sub>4</sub><br>D)HPO<sub>4</sub><sup>-2</sup><br>E)none

Q13: A substance that is capable of acting

Q18: What is the pH of an aqueous

Q20: Using the data in the table, which

Q36: Classify the following compounds as weak bases

Q52: Classify the following compounds as weak acids

Q68: Of the following,which is the strongest acid?<br>A)HClO<br>B)HClO<sub>3</sub><br>C)HClO<sub>2</sub><br>D)HClO<sub>4</sub><br>E)HIO

Q132: An aqueous solution contains 0.150 M HCl