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If You Draw a Card at Random from a Well-Shuffled

Question 47

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If you draw a card at random from a well-shuffled deck,is getting a club independent of getting a queen? Explain.


A) Yes.A card cannot be both a club and a queen.
B) No.The probability of getting a club and a queen is
If you draw a card at random from a well-shuffled deck,is getting a club independent of getting a queen? Explain. A) Yes.A card cannot be both a club and a queen. B) No.The probability of getting a club and a queen is   .This is not zero C) Yes.P(Club) =   ;P(Club|Queen) =   D) No.P(C and Q) ≠ P(C) ∙ P(Q)  E) No.P(Club) =   ;P(Club|Queen) =
.This is not zero
C) Yes.P(Club) =
If you draw a card at random from a well-shuffled deck,is getting a club independent of getting a queen? Explain. A) Yes.A card cannot be both a club and a queen. B) No.The probability of getting a club and a queen is   .This is not zero C) Yes.P(Club) =   ;P(Club|Queen) =   D) No.P(C and Q) ≠ P(C) ∙ P(Q)  E) No.P(Club) =   ;P(Club|Queen) =
;P(Club|Queen) =
If you draw a card at random from a well-shuffled deck,is getting a club independent of getting a queen? Explain. A) Yes.A card cannot be both a club and a queen. B) No.The probability of getting a club and a queen is   .This is not zero C) Yes.P(Club) =   ;P(Club|Queen) =   D) No.P(C and Q) ≠ P(C) ∙ P(Q)  E) No.P(Club) =   ;P(Club|Queen) =
D) No.P(C and Q) ≠ P(C) ∙ P(Q)
E) No.P(Club) =
If you draw a card at random from a well-shuffled deck,is getting a club independent of getting a queen? Explain. A) Yes.A card cannot be both a club and a queen. B) No.The probability of getting a club and a queen is   .This is not zero C) Yes.P(Club) =   ;P(Club|Queen) =   D) No.P(C and Q) ≠ P(C) ∙ P(Q)  E) No.P(Club) =   ;P(Club|Queen) =
;P(Club|Queen) =
If you draw a card at random from a well-shuffled deck,is getting a club independent of getting a queen? Explain. A) Yes.A card cannot be both a club and a queen. B) No.The probability of getting a club and a queen is   .This is not zero C) Yes.P(Club) =   ;P(Club|Queen) =   D) No.P(C and Q) ≠ P(C) ∙ P(Q)  E) No.P(Club) =   ;P(Club|Queen) =

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