Multiple Choice
How many grams of BaCl2 are formed when 35.00 mL of 0.00237 M Ba(OH) 2 reacts with excess Cl2 gas? 2 Ba(OH) 2(aq) + 2 Cl2(g) → Ba(OCl) 2(aq) + BaCl2(s) + 2 H2O(l)
A) 0.00864 g
B) 0.0173 g
C) 0.0346 g
D) 0.0829 g
Correct Answer:
Verified
Correct Answer:
Verified
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