Multiple Choice
What is the approximate value of the equilibrium constant,Kn,for the neutralization of acetic acid with potassium hydroxide,shown in the equation below? The Ka for acetic acid is 1.8 × 10-5. CH3CO2H(aq) + KOH(aq) ⇌ H2O(l) + NaCH3CO2(aq)
A) 1.8 × 10-19
B) 5.6 × 10-10
C) 1.8 × 10-8
D) 1.8 × 109
Correct Answer:
Verified
Correct Answer:
Verified
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