Multiple Choice
How many unpaired electrons are predicted for a tetrahedral iron (II) complex?
A) 5 or 1, depending on the ligands.
B) 0 or 4, depending on the ligands.
C) 1
D) 4
E) 5
Correct Answer:
Verified
Correct Answer:
Verified
Q81: Rhodium lies below cobalt in the periodic
Q82: Which of the following is likely to
Q83: How many unpaired electrons can be predicted
Q84: Which of the following pairs have about
Q85: The complex [Ru(OH<sub>2</sub>)<sub>3</sub>Cl<sub>3</sub>]<br>A) is chiral.<br>B) has 2
Q87: How many unpaired electrons are expected for
Q88: One mole of cis-tetraamminedichlororhodium(III) chloride dissolves in
Q89: Comparing [Co(CN)<sub>6</sub>]<sup>3</sup><sup>-</sup> with [CoCl<sub>6</sub>]<sup>4</sup><sup>-</sup>, which of the
Q90: The lanthanide contraction results because<br>A) the shielding
Q91: In the complex [Fe(CN)<sub>6</sub>]<sup>4</sup><sup>-</sup>,<br>A) iron is a