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Calculate Δ\Delta Ssurr° at 298 K for the Reaction
6C(s)+ 3H2(g) \rightarrow

Question 9

Multiple Choice

Calculate Δ\Delta Ssurr° at 298 K for the reaction
6C(s) + 3H2(g) \rightarrow C6H6(l)
Δ\Delta Hr° = +49.0 kJ.mol-1,
Δ\Delta Sr° = -253 J.K-1.mol-1


A) +164 J.K-1.mol-1
B) -417 J.K-1.mol-1
C) +253 J.K-1.mol-1
D) -164 J.K-1.mol-1
E) -253 J.K-1.mol-1

Correct Answer:

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