As Shown in the Figure, Charge Q₁ = 2 $10^{ - 6}$

Short Answer

As shown in the figure, charge q₁ = 2.2 x $10^{ - 6}$ C is placed at the origin and charge $9 _ { 2 } = - 3.30 \times 10 ^{- 6} C$ is placed on the $x - a \times i s$ at $x = - 0.200 \mathrm {~m}$ Where along the x-axis can a third charge Q = -8.30 × 10^-6 C be placed so that the resultant force on Q is zero?