Multiple Choice
A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg)
A) 7.66 × m/ opposite to the electric field
B) 7.66 × m/ opposite to the electric field
C) 7.66 × m/ in the direction of the electric field
D) 76.6 × m/ opposite to the electric field
E) 76.6 × m/ in the direction of the electric field
Correct Answer:

Verified
Correct Answer:
Verified
Q11: A small glass bead has been charged
Q15: Two tiny particles having charges of +7.00
Q19: A negatively-charged rod is brought close to
Q21: Three identical 3.0-µC charges are placed at
Q57: There is a +5.0-μC charge at three
Q58: Three equal negative point charges -q are
Q63: How far apart should two protons be
Q65: Two equally charged tiny spheres of
Q71: Two tiny particles having charges of +5.00
Q74: A hydrogen nucleus,which has a charge +e,is