Short Answer
A flat circular coil having 57 turns of very thin wire has a diameter of 9.5 cm and carries 7.2 A of current. (μ0 = 4π × 10-7 T ∙ m/A)
(a) What is the strength of the magnetic field at the center of the coil?
(b) If the same length of wire were used to make a coil with twice the original diameter, how large would the magnetic field at the center be when it carried the same current as before?
Correct Answer:

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(a) 5.4 mT...View Answer
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Correct Answer:
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