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Find the Correct Equilibrium Constant That Shows the Ionization Constant [HA][H3O+][A]\frac{[\mathrm{HA}]}{\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\left[\mathrm{A}^{-}\right]}

Question 33

Multiple Choice

Find the correct equilibrium constant that shows the ionization constant of a weak acid HA.


A) Ka = [HA][H3O+][A]\frac{[\mathrm{HA}]}{\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\left[\mathrm{A}^{-}\right]}
B) Ka = [H3O+][A][HA][H2O]\frac { \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] \left[ \mathrm { A } ^ { - } \right] } { [ \mathrm { HA } ] \left[ \mathrm { H } _ { 2 } \mathrm { O } \right] }
C) Ka = [H3O+][A][HA]\frac { \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] \left[ \mathrm { A } ^ { - } \right] } { [ \mathrm { HA } ] }
D) Ka = [HA][H2O][H3O+][A]\frac { [ \mathrm { HA } ] \left[ \mathrm { H } _ { 2 } \mathrm { O } \right] } { \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] \left[ \mathrm { A } ^ { - } \right] }
E) Ka = [A][HA]\frac{\left[\mathrm{A}^{-}\right]}{[\mathrm{HA}]}

Correct Answer:

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