Solved

Instruction 5 X0123p(X)0.350.350.250.05\begin{array} { | c | c | c | c | c | } \hline X & 0 & 1 & 2 & 3 \\\hline p ( X ) & 0.35 & 0.35 & 0.25 & 0.05 \\\hline\end{array}

Question 17

Short Answer

Instruction 5.1
The following table contains the probability distribution for X = the number of retransmissions necessary to successfully transmit a 1024K data package through a double satellite media.
X0123p(X)0.350.350.250.05\begin{array} { | c | c | c | c | c | } \hline X & 0 & 1 & 2 & 3 \\\hline p ( X ) & 0.35 & 0.35 & 0.25 & 0.05 \\\hline\end{array}
-Referring to Instruction 5.1,the probability of no retransmissions is ______.

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions