Short Answer
A proton is first accelerated from rest through a potential difference V and then enters a uniform 0.750-T magnetic field oriented perpendicular to its path.In this field,the proton follows a circular arc having a radius of curvature of 1.84 cm.What was the potential difference V? (mproton = 1.67 × 10-27 kg,
Correct Answer:

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Correct Answer:
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