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A Round Loop of Diameter 12 Cm,carrying a Current of 0.40

Question 6

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A round loop of diameter 12 cm,carrying a current of 0.40 A,is placed inside a magnetic field A round loop of diameter 12 cm,carrying a current of 0.40 A,is placed inside a magnetic field   = 0.20 T   + 0.40 T   .The normal to the loop is parallel to the unit vector   What is the potential energy of the loop? A)  -4.5 × 10<sup>-3</sup> J B)  +2.0 × 10<sup>-3</sup> J C)  -2.0 × 10<sup>-3</sup> J D)  -2.3 × 10<sup>-3</sup> J E)  +4.5 × 10<sup>-3</sup> J = 0.20 T A round loop of diameter 12 cm,carrying a current of 0.40 A,is placed inside a magnetic field   = 0.20 T   + 0.40 T   .The normal to the loop is parallel to the unit vector   What is the potential energy of the loop? A)  -4.5 × 10<sup>-3</sup> J B)  +2.0 × 10<sup>-3</sup> J C)  -2.0 × 10<sup>-3</sup> J D)  -2.3 × 10<sup>-3</sup> J E)  +4.5 × 10<sup>-3</sup> J + 0.40 T A round loop of diameter 12 cm,carrying a current of 0.40 A,is placed inside a magnetic field   = 0.20 T   + 0.40 T   .The normal to the loop is parallel to the unit vector   What is the potential energy of the loop? A)  -4.5 × 10<sup>-3</sup> J B)  +2.0 × 10<sup>-3</sup> J C)  -2.0 × 10<sup>-3</sup> J D)  -2.3 × 10<sup>-3</sup> J E)  +4.5 × 10<sup>-3</sup> J .The normal to the loop is parallel to the unit vector A round loop of diameter 12 cm,carrying a current of 0.40 A,is placed inside a magnetic field   = 0.20 T   + 0.40 T   .The normal to the loop is parallel to the unit vector   What is the potential energy of the loop? A)  -4.5 × 10<sup>-3</sup> J B)  +2.0 × 10<sup>-3</sup> J C)  -2.0 × 10<sup>-3</sup> J D)  -2.3 × 10<sup>-3</sup> J E)  +4.5 × 10<sup>-3</sup> J What is the potential energy of the loop?


A) -4.5 × 10-3 J
B) +2.0 × 10-3 J
C) -2.0 × 10-3 J
D) -2.3 × 10-3 J
E) +4.5 × 10-3 J

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