Multiple Choice
If E for the following cell is 0.36 V at 25 C Pb(s) |PbSO4(s) |SO42-(aq,0.60 M) m H+(aq,0.70 M) |H2(g,192.5 kPa) |Pt
How is the Nernst equation for the cell properly expressed at this temperature?
A) E = 0.36 - 0.01285ln[1.90/{(0.70) 2(0.60) }]
B) E = 0.36 - 0.02569ln[192.5/{(0.70) 2(0.60) }]
C) E = 0.36 + 0.01285ln[192.5/{(0.70) 2(0.60) }]
D) E = 0.36 + 0.01285ln[1.90/{(0.70) 2(0.60) }]
E) E = 0.36 - 0.01285ln[1.90/{(0.70) (0.60) }]
Correct Answer:

Verified
Correct Answer:
Verified
Q58: For the cell diagram Pt|H<sub>2</sub>(g),H<sup>+</sup>(aq)m Cu<sup>2+</sup>(aq)|Cu(s)<br>Which
Q59: Given: S<sub>2</sub>O<sub>4</sub><sup>2</sup><sup>-</sup>(aq) <span class="ql-formula" data-value="\rightarrow"><span class="katex"><span
Q61: If the standard free energy change for
Q62: A cell that uses bromine to oxidize
Q65: The products of the electrolysis of CuSO<sub>4</sub>(aq)are<br>A)H<sub>2</sub>(g)and
Q66: Calculate E<sup> <span class="ql-formula" data-value="\circ"><span class="katex"><span
Q67: The standard potential of the cell
Q68: If 8686 C of charge is passed
Q229: Consider the following cell:<br>Zn(s)|Zn<sup>2+</sup>(aq,0.10 M)m Cu<sup>2+</sup>(aq,0.10 M)|Cu(s)<br>At
Q264: What is E for the half-reaction