Multiple Choice
According to the following reaction,what mass of PbCl2 can form from 235 mL of 0.110 M KCl solution? Assume that there is excess Pb(NO3) 2. 2 KCl(aq) + Pb(NO3) 2(aq) → PbCl2(s) + 2 KNO3(aq)
A) 7.19 g
B) 3.59 g
C) 1.80 g
D) 5.94 g
E) 1.30 g
Correct Answer:

Verified
Correct Answer:
Verified
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