Multiple Choice
Select the best explanation for why methanol, CH3OH, cannot be used as a solvent for the deprotonation of a terminal alkyne by sodium amide, NaNH2.
A) Sodium amide is not a strong enough base to deprotonate the alkyne.
B) Sodium amide in methanol reduces alkynes to alkenes.
C) Methanol is a poor solvent for dissolving alkynes.
D) Methanol is more acidic than the alkyne and will be deprotonated instead.
E) Methanol is toxic, and should be avoided when possible.
Correct Answer:

Verified
Correct Answer:
Verified
Q145: Rank the following bases in order of
Q146: Which of the following is the structure
Q147: Which of the reagents below would convert
Q148: Provide the IUPAC name for Cl<sub>3</sub>C(CH<sub>2</sub>)<sub>4</sub>C≡CH.<br>A) 4,4,4-trichloro-1-butyne<br>B)
Q149: Identify the major product. <img src="https://d2lvgg3v3hfg70.cloudfront.net/TB4454/.jpg" alt="Identify
Q151: What is the final major product expected
Q152: Identify the functional group would be expected
Q153: Identify the expected major product from the
Q154: How many distinct eight-carbon hydrocarbon products would
Q155: Which of the following statements is true