Solved

Aluminum Oxide (Used as an Adsorbent or a Catalyst for Organic

Question 55

Multiple Choice

Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen.
4Al(s) + 3O2(g) \to 2Al2O3(s)
A mixture of 82.49 g of aluminum (  Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen. 4Al(s) + 3O<sub>2</sub>(g)   \to  2Al<sub>2</sub>O<sub>3</sub>(s)  A mixture of 82.49 g of aluminum (   = 26.98 g/mol) and 117.65 g of oxygen (   = 32.00 g/mol) is allowed to react.What mass of aluminum oxide (   = 101.96 g/mol) can be formed? A) 155.8 g B) 200.2 g C) 249.9 g D) 311.7 g E) 374.9 g
= 26.98 g/mol) and 117.65 g of oxygen (  Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen. 4Al(s) + 3O<sub>2</sub>(g)   \to  2Al<sub>2</sub>O<sub>3</sub>(s)  A mixture of 82.49 g of aluminum (   = 26.98 g/mol) and 117.65 g of oxygen (   = 32.00 g/mol) is allowed to react.What mass of aluminum oxide (   = 101.96 g/mol) can be formed? A) 155.8 g B) 200.2 g C) 249.9 g D) 311.7 g E) 374.9 g
= 32.00 g/mol) is allowed to react.What mass of aluminum oxide (  Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen. 4Al(s) + 3O<sub>2</sub>(g)   \to  2Al<sub>2</sub>O<sub>3</sub>(s)  A mixture of 82.49 g of aluminum (   = 26.98 g/mol) and 117.65 g of oxygen (   = 32.00 g/mol) is allowed to react.What mass of aluminum oxide (   = 101.96 g/mol) can be formed? A) 155.8 g B) 200.2 g C) 249.9 g D) 311.7 g E) 374.9 g
= 101.96 g/mol) can be formed?


A) 155.8 g
B) 200.2 g
C) 249.9 g
D) 311.7 g
E) 374.9 g

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions