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The Figure Shows Two Forces Acting on an Object

Question 33

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The figure shows two forces acting on an object.They have magnitudes F1 = 6.3 N and F2 = 2.1 N.What third force will cause the object to be in equilibrium? The figure shows two forces acting on an object.They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N.What third force will cause the object to be in equilibrium?   A) 6.6 N at 162° counterclockwise from   B) 6.6 N at 108° counterclockwise from   C) 4.2 N at 162° counterclockwise from   D) 4.2 N at 108° counterclockwise from


A) 6.6 N at 162° counterclockwise from The figure shows two forces acting on an object.They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N.What third force will cause the object to be in equilibrium?   A) 6.6 N at 162° counterclockwise from   B) 6.6 N at 108° counterclockwise from   C) 4.2 N at 162° counterclockwise from   D) 4.2 N at 108° counterclockwise from
B) 6.6 N at 108° counterclockwise from The figure shows two forces acting on an object.They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N.What third force will cause the object to be in equilibrium?   A) 6.6 N at 162° counterclockwise from   B) 6.6 N at 108° counterclockwise from   C) 4.2 N at 162° counterclockwise from   D) 4.2 N at 108° counterclockwise from
C) 4.2 N at 162° counterclockwise from The figure shows two forces acting on an object.They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N.What third force will cause the object to be in equilibrium?   A) 6.6 N at 162° counterclockwise from   B) 6.6 N at 108° counterclockwise from   C) 4.2 N at 162° counterclockwise from   D) 4.2 N at 108° counterclockwise from
D) 4.2 N at 108° counterclockwise from The figure shows two forces acting on an object.They have magnitudes F<sub>1</sub> = 6.3 N and F<sub>2</sub> = 2.1 N.What third force will cause the object to be in equilibrium?   A) 6.6 N at 162° counterclockwise from   B) 6.6 N at 108° counterclockwise from   C) 4.2 N at 162° counterclockwise from   D) 4.2 N at 108° counterclockwise from

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