Multiple Choice
A proton with a speed of 2.0 x 105 m/s falls through a potential difference V and thereby increases its speed to 4.0 × 105 m/s.Through what potential difference did the proton fall?
A) 630 V
B) 210 V
C) 840 V
D) 1000 V
E) 100 V
Correct Answer:
Verified
Correct Answer:
Verified
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