Instruction 16-5
a Chemist Employed by a Pharmaceutical Firm Has

Short Answer

Instruction 16-5
A chemist employed by a pharmaceutical firm has developed a muscle relaxant.She took a sample of 14 people suffering from extreme muscle constriction.She gave each a vial containing a dose (X)of the drug and recorded the time to relief (Y)measured in seconds for each.She fit a quadratic model to this data.The results obtained by Microsoft Excel follow.
$\begin{array}{l|l|l|l|l|l|}\text { SUMMARY } & output& \\\hline \text { Regression } & \text { Statistics } & \\\hline \text { Multiple R } & & 0.747 \\\hline \text { R Square } & & 0.558 \\\hline \text { Adj. R Square } & & 0.478 \\\hline \text { Std. Error } & 363.1 \\\hline \text { Observations } & 14 \\\hline\\\hline \text { ANOVA } & & & & & \\\hline & \text { df } & \text { SS } & \text { MS } & F & \text { Signưf } F \\\hline \text { Regression } & 2 & 10344797 & 5172399 & 6.94 & 0.0110 \\\hline \text { Residual } & 11 & 8193929 & 744903 & & \\\hline \text { Total } & 13 & 18538726 & & & \\\hline\\\hline & \text { Coeff } & \text { StdErior } & \text { Stat } & P \text {-value } \\\hline \text { Intercept } & 1283.0 & 352.0 & 3.65 & 0.0040 \\\hline \text { CenDose } & 25.228 & 3.631 & 2.92 & 0.0140 \\\hline \text { CenDoseSq } & 0.8604 & 0.3722 & 2.31 & 0.0410\\\hline\end{array}$ Note: Adj.R Square = Adjusted R Square;Std.Error = Standard Error
-Referring to Instruction 16-5,the prediction of time to relief for a person receiving a dose of the drug 10 units above the average dose ,is ________.