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Solve the Equation 2y23y3=02 y ^ { 2 } - 3 y - 3 = 0

Question 16

Multiple Choice

Solve the equation. 2y23y3=02 y ^ { 2 } - 3 y - 3 = 0


A) y=34±33y = \frac { 3 } { 4 } \pm \sqrt { 33 }
B) y=3±336y = \frac { - 3 \pm \sqrt { 33 } } { 6 }
C) y=35±32y = \frac { \sqrt { 35 } \pm 3 } { 2 }
D) y=3±353y = \frac { 3 \pm \sqrt { 35 } } { 3 }
E) y=3±334y = \frac { 3 \pm \sqrt { 33 } } { 4 }

Correct Answer:

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