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The Radioactive Bismuth Isotope 210 Bi Has a Half-Life f(t)=100(2)t5f ( t ) = 100 ( 2 ) ^ { - \frac { t } { 5 } }

Question 11

Multiple Choice

The radioactive bismuth isotope 210 Bi has a half-life of 5 days. If there is 100 milligrams of 210 Bi present at t = 0, then the amount f(t) remaining after t days is given by: f(t) =100(2) t5f ( t ) = 100 ( 2 ) ^ { - \frac { t } { 5 } } How much 210 Bi remains after 25 days?


A) 3.125 milligrams
B) 12.125 milligrams
C) 5.125 milligrams
D) 8.125 milligrams
E) 2.125 milligrams

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