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  2. Topic
    Mathematics
  3. Study Set
    Applied Calculus
  4. Exam
    Exam 9: Infinite Series and Taylor Series Approximations
  5. Question
    The Given Series Converges\(\sum _ { k = 1 } ^ { \infty } \frac { k - 9 } { k ^ { 2 } + 6 }\)
Solved

The Given Series Converges ∑k=1∞k−9k2+6\sum _ { k = 1 } ^ { \infty } \frac { k - 9 } { k ^ { 2 } + 6 }∑k=1∞​k2+6k−9​

Question 3

Question 3

True/False

The given series converges. ∑k=1∞k−9k2+6\sum _ { k = 1 } ^ { \infty } \frac { k - 9 } { k ^ { 2 } + 6 }∑k=1∞​k2+6k−9​

Correct Answer:

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