Determine the Integral by Making an Appropriate Substitution $\int 8 x \sqrt [ 3 ] { 4 x ^ { 2 } - 9 }$

Multiple Choice

Determine the integral by making an appropriate substitution.
- $\int 8 x \sqrt [ 3 ] { 4 x ^ { 2 } - 9 }$ dx

A) $\frac { \left( 4 x ^ { 2 } + 9 \right) ^ { 4 } } { 16 }$ + C
B) $\frac { \left( 4 x ^ { 2 } - 9 \right) ^ { 4 / 3 } } { 3 }$ + C
C) $\frac { 3 \left( 4 x ^ { 2 } + 9 \right) ^ { 4 / 3 } } { 4 }$ + C
D) $\frac { 3 \left( 4 x ^ { 2 } - 9 \right) ^ { 4 / 3 } } { 4 }$ + C