Find T Such That - $\frac { \pi } { 2 }$

Short Answer

Find t such that - $\frac { \pi } { 2 }$ ≤ t ≤ $\frac { \pi } { 2 }$ and sin t = sin $\left( \frac { 10 \pi } { 3 } \right)$ .
Enter just a reduced quotient of form $\frac { a } { b }$ with π in the numerator (unlabeled).