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Let F(x, Y) = Ln(x + 2y) 2fxy\frac { \partial ^ { 2 } \mathrm { f } } { \partial \mathrm { x } \partial \mathrm { y } }

Question 58

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Let f(x, y) = ln(x + 2y). Find 2fxy\frac { \partial ^ { 2 } \mathrm { f } } { \partial \mathrm { x } \partial \mathrm { y } } . Is (x+2y)2- ( x + 2 y ) ^ { 2 } the correct answer?

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