In the figure below, the region enclosed by the curves y = -

\frac { 4 } { x }

, y = -x, and y = -x + 3 is shown. Set up an integral or sum of integrals to find the area of the shaded region. (Do not calculate the area.) $In the figure below, the region enclosed by the curves y = - \frac { 4 } { x } , y = -x, and y = -x + 3 is shown. Set up an integral or sum of integrals to find the area of the shaded region. (Do not calculate the area.) A) \int _ { - 2 } ^ { - 1 } \left( - \frac { 4 } { x } + x \right) d x + \int _ { - 1 } ^ { 2 } 3 d x + \int _ { 2 } ^ { 4 } \left( - x + 3 + \frac { 4 } { x } \right) d x B) \int _ { - 2 } ^ { 2 } 3 \mathrm { dx } \int _ { 2 } ^ { 4 } \left( - x + 3 - \frac { 4 } { x } \right) \mathrm { dx } C) \int _ { - 2 } ^ { 0 } \left( - \frac { 4 } { x } + x \right) d x + \int _ { 0 } ^ { 2 } \left( - x + 3 + \frac { 4 } { x } \right) d x D) \int _ { - 2 } ^ { 4 } 3 d x E) none of these$
A)

\int _ { - 2 } ^ { - 1 } \left( - \frac { 4 } { x } + x \right) d x

\int _ { - 1 } ^ { 2 } 3 d x

\int _ { 2 } ^ { 4 } \left( - x + 3 + \frac { 4 } { x } \right) d x

\int _ { - 2 } ^ { 2 } 3 \mathrm { dx } \int _ { 2 } ^ { 4 } \left( - x + 3 - \frac { 4 } { x } \right) \mathrm { dx }

\int _ { - 2 } ^ { 0 } \left( - \frac { 4 } { x } + x \right) d x

\int _ { 0 } ^ { 2 } \left( - x + 3 + \frac { 4 } { x } \right) d x

\int _ { - 2 } ^ { 4 } 3 d x

E) none of these

A Region Is Bounded Above by the Graph of Y x−2x ^ { - 2 }x−2

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A Region Is Bounded Above by the Graph of Y $x ^ { - 2 }$

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