Compute the Maximum Profit When the Demand Function Is $p ( x ) = x ^ { 2 } - 3 x + 2$

Short Answer

Compute the maximum profit when the demand function is $p ( x ) = x ^ { 2 } - 3 x + 2$ and the total cost function is $C ( x ) = \frac { 2 x ^ { 3 } } { 3 } - \frac { 1 } { 2 } x ^ { 2 } - 2 x$ Enter just a reduced fraction of form $\frac { a } { b }$ .