Find (By Inspection) the Expected Value and the Variance of the Random

Short Answer

Find (by inspection) the expected value and the variance of the random variables with the following density function: f(x) = $\frac { 1 } { 4 \sqrt { 2 \pi } }$ $\mathrm { e } ^ { - ( 1 / 2 ) [ ( \mathrm { x } - 1 ) / 4 ] ^ { 2 } }$ , -∞ < x < ∞
Enter your answer as just two integers separated by a comma, the first representing E(X) and the second representing Var(X).