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Given the Differential Equation with the Given Initial Condition y=tcost;y(0)=0\mathrm { y } ^ { \prime } = \mathrm { t } \cos \mathrm { t } ; \mathrm { y } ( 0 ) = 0

Question 43

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Given the differential equation with the given initial condition: y=tcost;y(0)=0\mathrm { y } ^ { \prime } = \mathrm { t } \cos \mathrm { t } ; \mathrm { y } ( 0 ) = 0 is this the solution y=tsint+cost1?y = t \sin t + \cos t - 1 ?

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