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Given the Differential Equation with the Given Initial Condition yy=tet2;y(0)=1y y ^ { \prime } = \operatorname { te } ^ { \mathrm { t } ^ { 2 } } ; \quad y ( 0 ) = 1

Question 82

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Given the differential equation with the given initial condition: yy=tet2;y(0)=1y y ^ { \prime } = \operatorname { te } ^ { \mathrm { t } ^ { 2 } } ; \quad y ( 0 ) = 1 is this the solution y=et2/2?y = e ^ { t ^ { 2 } / 2 } ?

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