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Given the Differential Equation with the Given Initial Condition dydt=3t2+sint;y(0)=2\frac { d y } { d t } = 3 t ^ { 2 } + \sin t ; y ( 0 ) = 2

Question 34

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Given the differential equation with the given initial condition: dydt=3t2+sint;y(0)=2\frac { d y } { d t } = 3 t ^ { 2 } + \sin t ; y ( 0 ) = 2 is this the solution y=t3cost+1?y = t ^ { 3 } - \cos t + 1 ?

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