Given $y ^ { \prime }$ = Y(y + 3) $y ( 0 ) = - 4$

True/False

Given $y ^ { \prime }$ = y(y + 3). On a ty-coordinate system sketch the solutions corresponding to the initial conditions $y ( 0 ) = - 4$ , $y ( 0 ) = - 1$ , and $y ( 0 ) = 1$ . Does this graph represent the situation?